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Test 3 · Rodents of every kind: squirrels, marmots, prairie dogs, p…

Count them: a flying squirrel has a skin flap on each side between its front and back legs. How many flaps do 3 flying squirrels have?

Mova's choice: option 1 · The right answer: option 1 · right ✓ · Who acts: you, flying squirrel, many flaps, 3 flying squirrels · What happens: count, fly, have, do · To what, where: them, skin flap, side

This is test 3 of lesson 317 «Rodents of every kind: squirrels, marmots, prairie dogs, porcupines, chinchillas and dormice» of the biology course of Mova's primary school. The page gives the question's syntax tree — a dependency tree in the style of Universal Dependencies — and its pragmatics clause by clause, then the 4 options as the student saw them, each with its tree and pragmatics. Every text is parsed by Mova itself. How the student answered it, with the score of every option and why: the test at school.

The question

Sentence 1: Count them: a flying squirrel has a skin flap on each side between its front and back legs.

objpunctdetamodnsubjparataxisdetcompoundobjcasedetnmodcasenmod:possamodccconjnmodpunctrootCountVERBthemPRON:PUNCTaDETflyingVERBsquirrelNOUNhasVERBaDETskinNOUNflapNOUNonADPeachDETsideNOUNbetweenADPitsPRONfrontADJandCCONJbackADJlegsNOUN.PUNCT
The words, one row each (CoNLL-U)
#wordlemmaUPOSfeaturesheadrelation
1CountcountVERBMood=Imp VerbForm=Finrootroot
2themtheyPRONCase=Acc Number=Plur Person=3 PronType=Prs1 Countobj
3::PUNCT_7 haspunct
4aaDETDefinite=Ind PronType=Art6 squirreldet
5flyingflyVERBVerbForm=Ger6 squirrelamod
6squirrelsquirrelNOUNNumber=Sing7 hasnsubj
7hashaveVERBMood=Ind Number=Sing Person=3 Tense=Pres VerbForm=Fin1 Countparataxis
8aaDETDefinite=Ind PronType=Art10 flapdet
9skinskinNOUNNumber=Sing10 flapcompound
10flapflapNOUNNumber=Sing7 hasobj
11ononADP_13 sidecase
12eacheachDETPronType=Tot13 sidedet
13sidesideNOUNNumber=Sing10 flapnmod
14betweenbetweenADP_19 legscase
15itsitsPRONCase=Gen Gender=Neut Number=Sing Person=3 Poss=Yes PronType=Prs19 legsnmod:poss
16frontfrontADJDegree=Pos19 legsamod
17andandCCONJ_18 backcc
18backbackADJDegree=Pos16 frontconj
19legslegNOUNNumber=Plur13 sidenmod
20..PUNCT_1 Countpunct
#verbtense, moodwhowhat, whomto whomwherewhenotherroles by
1countimperativeyou not said herethem = theyvn multiply-108 «NP V NP»: agent=Agent they=Theme
2flygerundvn spatial_configuration-47.6-1 «NP V»: agent=Theme
3havepresenta flying squirrela skin flapeach side between squirrel's front legsvn birth-28.2-1 «NP V NP»: agent=Agent flap=Patient

One row per clause the reader finds. «not said here»: a role filled from the clause above. «roles by»: a VerbNet class and frame when one fits the verb, else the reader's rules on the tree.

Sentence 2: How many flaps do 3 flying squirrels have?

advmodamodnsubjnummodamodnsubjccomppunctrootHowADVmanyADJflapsNOUNdoVERB3NUMflyingVERBsquirrelsNOUNhaveVERB?PUNCT
The words, one row each (CoNLL-U)
#wordlemmaUPOSfeaturesheadrelation
1HowhowADVPronType=Int2 manyadvmod
2manymanyADJDegree=Pos3 flapsamod
3flapsflapNOUNNumber=Plur4 donsubj
4dodoVERBMood=Ind Number=Plur Person=3 Tense=Pres VerbForm=Finrootroot
533NUMNumForm=Digit NumType=Card7 squirrelsnummod
6flyingflyVERBVerbForm=Ger7 squirrelsamod
7squirrelssquirrelNOUNNumber=Plur8 havensubj
8havehaveVERBMood=Ind Number=Plur Person=3 Tense=Pres VerbForm=Fin4 doccomp
9??PUNCT_4 dopunct
#verbtense, moodwhowhat, whomto whomwherewhenotherroles by
1dopresentmany flapstree rules
2flygerundvn spatial_configuration-47.6-1 «NP V»: agent=Theme
3havepresent3 flying squirrelsvn birth-28.2-1 «NP V NP»: agent=Agent

The options

Option 1 · ← Mova's choice · ✓ the right answer

6

root6NUM
The words, one row each (CoNLL-U)
#wordlemmaUPOSfeaturesheadrelation
166NUMNumForm=Digit NumType=Cardrootroot

The frames reader finds no event or fact in this sentence.

Option 2

9

root9NUM
The words, one row each (CoNLL-U)
#wordlemmaUPOSfeaturesheadrelation
199NUMNumForm=Digit NumType=Cardrootroot

The frames reader finds no event or fact in this sentence.

Option 3

12

root12NUM
The words, one row each (CoNLL-U)
#wordlemmaUPOSfeaturesheadrelation
11212NUMNumForm=Digit NumType=Cardrootroot

The frames reader finds no event or fact in this sentence.

Option 4

3

root3NUM
The words, one row each (CoNLL-U)
#wordlemmaUPOSfeaturesheadrelation
133NUMNumForm=Digit NumType=Cardrootroot

The frames reader finds no event or fact in this sentence.

Text: the tests of Mova's primary school, written for Mova (world/data/school/), as the course runner gave them to the student. Trees: Mova's own parse — the en model on the CPU, when the site is built — not checked by a teacher; they may be wrong. Frames: Mova's frames reader (prag), each text read on its own. Elamur Cosmic License.

This page in Markdown → https://md.mova.elamur.ai/free/en/corpora/questions/biology/317-rodents-of-every-kind-squirrels-marmots-prairie-dogs-porcupines-chinchillas-and-dormice/t3/